[BOJ 12205] Parentheses Order (Large)
View as PDFAn n parentheses sequence consists of n (s and n )s.</p>
A valid parentheses sequence is defined as the following:
You can find a way to repeat erasing adjacent pair of parentheses () until it becomes empty.
For example, (()) is a valid parentheses, you can erase the pair on the 2nd and 3rd position and it becomes () then you can make it empty. )()( is not a valid parentheses, after you erase the pair on the 2nd and 3rd position, it becomes )( and you cannot erase any more.
Now, we have all valid n parentheses sequences. Find the k-th smallest sequence in lexicographical order.
For example, here are all valid 3 parentheses sequences in lexicographical order:
((())) (()()) (())() ()(()) ()()()## 입력 형식
The first line of the input gives the number of test cases, T. T lines follow. Each line represents a test case consisting of 2 integers, n and k.
출력 형식
For each test case, output one line containing "Case #x: y", where x is the test case number (starting from 1) and y is the k-th smallest parentheses sequence in all valid n parentheses sequences. Output "Doesn't Exist!" when there are less than k different n parentheses sequences.
예제 입력
3
2 2
3 4
3 6
예제 출력
Case #1: ()()
Case #2: ()(())
Case #3: Doesn't Exist!
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