In this problem, you have to find the last three digits before the decimal point for the number (3 + √5)ⁿ.</p>

For example, when n = 5, (3 + √5)⁵ = 3935.73982... The answer is 935.

For n = 2, (3 + √5)² = 27.4164079... The answer is 027.

입력 형식

The first line of input gives the number of cases, T. T test cases follow, each on a separate line. Each test case contains one positive integer n.</p>

Limits

• 1 <= T <= 100
• 2 <= n <= 30

For each input case, you should output:

Case #X: Y

where X is the number of the test case and Y is the last three integer digits of the number (3 + √5)ⁿ. In case that number has fewer than three integer digits, add leading zeros so that your output contains exactly three digits.

예제 입력

2
5
2

예제 출력

Case #1: 935
Case #2: 027